Chemistry, asked by sagarkaitake, 6 months ago

the bond order in B2 molecule is

Answers

Answered by vishnuanandhan302
3

Answer:

So the bond order of B2 is equal to 1, which you can

get by drawing the molecular orbital

diagram and performing the equation

Bond order = .5 * (# of bonding electrons - # of

anti bonding electrons ).

However ,when draw the Lewis structure of

B2 ,you get a triple bond.

Answered by ulagiyan
1

Answer:

So the bond order of B2 is equal to 1, which you can get by drawing the molecular orbital diagram and performing the equation Bond Order = . 5 * (# of bonding electrons - # of antibonding electrons). However, when you draw the Lewis structure of B2, you get a triple bond.

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