Chemistry, asked by ashmanikhatun5, 9 months ago

the bond order of s-o bond in so4'2-​

Answers

Answered by ambresahil33
1

Answer:

ANSWER = 1.5

Explanation:

Hybridization of so42- = 4 lone pair is 4-4 =0 [ 4= tot no.of oxygen atom ] bond order = valance electron - lone electrons/no. Atoms present along with central atom so answer = 1.5

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