the book says that the answer to this question is 39,945cm squared, but I am not able to get the same answer as in the book. how do I solve this to get this answer. And yeah ignore what I have written over the figure with the pencil
Answers
Answer:
idk
Step-by-step explanation:
maybe the book is wrong so we never k
Answer:
39.945 cm²
I have got the right answer, see below for steps and solution.
Step-by-step explanation:
Solving the question according to figure.
Given :-
A figure having 4 right-angled triangles and a Trapezium.
Triangle APE with base 90 cm and height 95 cm.
Triangle AQB with base 210 cm (90+120) and height 76 cm.
Triangle BQC with base 130 cm (30+100) and height 76 cm.
Triangle DRC with base 100 cm and height 125 cm
Trapezium DEPR with parallel sides of length 95 cm and 125 cm and height 150 cm (120+30).
Finding area for each segment :-
For right-angled triangle APE,
Area = 1/2 * Base * Height
= 1/2 * 90 * 95
= 45 * 95
= 4275 cm²
For right-angled triangle AQB,
Area = 1/2 * Base * Height
= 1/2 * 210 * 76
= 105 * 76
= 7980 cm²
For right-angled triangle BQC,
Area = 1/2 * Base * Height
= 1/2 * 130 * 76
= 65 * 76
= 4940 cm²
For right-angled triangle DRC,
Area = 1/2 * Base * Height
= 1/2 * 100 * 125
= 50 * 125
= 6250 cm²
For trapezium DEPR,
Area = 1/2 * Sum of parallel sides * Height
= 1/2 * (95+125) * 150
= 1/2 * 220 * 150
= 110 * 150
= 16500 cm²
Now, for area of the figure,
Area of triangle APE + Area of triangle AQB + Area of triangle + BQC + Area of triangle DRC + Area of trapezium DEPR
4275 cm² + 7980 cm² + 4940 cm² + 6250 cm² + 16500 cm²
39,945 cm²
Hence, the area of the figure is 39.945 cm².
Hope it helps you :)