Math, asked by guru27prasad2000, 11 months ago

the bottom of a right cylindrical shaped vessel made from metallic sheet is closed by a cone shaped vessel as shown in the figure .The radius of the circular base of the cone are each equal to 7cm .if the height of the cylinder is 20 cm and height of cone is 3cm,calculate the cost of milk to fill completely this vessel at the rate of Rs.20 per litte.​

Answers

Answered by generalRd
36

ANSWER

Volume of Container = 3234cm^3

Cost of milk  in container = Rs 64.68

Step By Step Explanations

Plz refer  the attachment for a detailed answer with diagram.

Remember

1) 1000 cm^3 = 1litre.

2) Volume of Cone = 1/3\times\pi r^2\times h

3)Volume of Cylinder =

\pi\times r^2\times h

Attachments:

siddhartharao77: Good
akashnayakubl: wrong answer buddy...its 58.5
shreya3680: the answer os wrong along with the diagram
Answered by UltimateMasTerMind
36

Solution:-

Given:-

For Cylindrical Part,

Height = 20cm.

Radius = 7cm.

=> Volume of The Cylindrical Part = πr²h

=> Volume = 22/7 × 7 × 7 × 20

=> Volume = 3080 cm³.

For Conical Part,

Height= 3cm

Radius= 7cm.

=> Volume of Conical Part= 1/3 πr²h

=> Volume = 1/3 × 22/7 × 7 × 7 × 3

=> Volume= 154cm³.

Hence,

Volume of Container = Volume of Conical part + Volume of Cylindrical part.

=> 154 + 3080

=> 3234cm³.

We know that,

1 Litre = 1000 cm³.

=> 3234 cm³ = 3234/1000 = 3.234 litre.

Now,

Cost of 1 Litre milk = ₹20

=> Cost of 3.234 litre of milk = 3.234 × 20

=> Cost of 3.234 Litre of milk= ₹ 64.68.

Attachments:

guru27prasad2000: Bro,that diagram is wrong, so the calculation also
shreya3680: the problem is wrong along with the diagram
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