Question

the bowler bowls at a speed of 180km/hr.how far will the ball travel in one second?​

Answer 1

Answer:

the ball will travel 50 cm= 0.5m=0.005km in one second

Answer 2

Answer

1.58N

explanation:

explanation:Speed =143 km/hr;

explanation:Speed =143 km/hr;Distance=63 m;

explanation:Speed =143 km/hr;Distance=63 m;As given the speed value in km/hr, we need to convert it into m/sec,

explanation:Speed =143 km/hr;Distance=63 m;As given the speed value in km/hr, we need to convert it into m/sec,km/hr to m/sec=1000/3600;

explanation:Speed =143 km/hr;Distance=63 m;As given the speed value in km/hr, we need to convert it into m/sec,km/hr to m/sec=1000/3600;Substitute the above value in to the speed value which is 143km/hr,

explanation:Speed =143 km/hr;Distance=63 m;As given the speed value in km/hr, we need to convert it into m/sec,km/hr to m/sec=1000/3600;Substitute the above value in to the speed value which is 143km/hr,Therefore 143 km/hr to m/sec

explanation:Speed =143 km/hr;Distance=63 m;As given the speed value in km/hr, we need to convert it into m/sec,km/hr to m/sec=1000/3600;Substitute the above value in to the speed value which is 143km/hr,Therefore 143 km/hr to m/sec=>143 x 1000/3600

explanation:Speed =143 km/hr;Distance=63 m;As given the speed value in km/hr, we need to convert it into m/sec,km/hr to m/sec=1000/3600;Substitute the above value in to the speed value which is 143km/hr,Therefore 143 km/hr to m/sec=>143 x 1000/3600Simplification of 1000/3600 is 5/18, substitute this in the above

explanation:Speed =143 km/hr;Distance=63 m;As given the speed value in km/hr, we need to convert it into m/sec,km/hr to m/sec=1000/3600;Substitute the above value in to the speed value which is 143km/hr,Therefore 143 km/hr to m/sec=>143 x 1000/3600Simplification of 1000/3600 is 5/18, substitute this in the above=>143 x 5/18

explanation:Speed =143 km/hr;Distance=63 m;As given the speed value in km/hr, we need to convert it into m/sec,km/hr to m/sec=1000/3600;Substitute the above value in to the speed value which is 143km/hr,Therefore 143 km/hr to m/sec=>143 x 1000/3600Simplification of 1000/3600 is 5/18, substitute this in the above=>143 x 5/18After multiplying we get the value in m/sec which is 39.72,

explanation:Speed =143 km/hr;Distance=63 m;As given the speed value in km/hr, we need to convert it into m/sec,km/hr to m/sec=1000/3600;Substitute the above value in to the speed value which is 143km/hr,Therefore 143 km/hr to m/sec=>143 x 1000/3600Simplification of 1000/3600 is 5/18, substitute this in the above=>143 x 5/18After multiplying we get the value in m/sec which is 39.72,=>39.72 m/sec

explanation:Speed =143 km/hr;Distance=63 m;As given the speed value in km/hr, we need to convert it into m/sec,km/hr to m/sec=1000/3600;Substitute the above value in to the speed value which is 143km/hr,Therefore 143 km/hr to m/sec=>143 x 1000/3600Simplification of 1000/3600 is 5/18, substitute this in the above=>143 x 5/18After multiplying we get the value in m/sec which is 39.72,=>39.72 m/secFrom the question, we need to find how much force should be applied from the batsman to hit a six,

explanation:Speed =143 km/hr;Distance=63 m;As given the speed value in km/hr, we need to convert it into m/sec,km/hr to m/sec=1000/3600;Substitute the above value in to the speed value which is 143km/hr,Therefore 143 km/hr to m/sec=>143 x 1000/3600Simplification of 1000/3600 is 5/18, substitute this in the above=>143 x 5/18After multiplying we get the value in m/sec which is 39.72,=>39.72 m/secFrom the question, we need to find how much force should be applied from the batsman to hit a six,Force=63/39.72

explanation:Speed =143 km/hr;Distance=63 m;As given the speed value in km/hr, we need to convert it into m/sec,km/hr to m/sec=1000/3600;Substitute the above value in to the speed value which is 143km/hr,Therefore 143 km/hr to m/sec=>143 x 1000/3600Simplification of 1000/3600 is 5/18, substitute this in the above=>143 x 5/18After multiplying we get the value in m/sec which is 39.72,=>39.72 m/secFrom the question, we need to find how much force should be applied from the batsman to hit a six,Force=63/39.72Force=1.58N

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