Question

The bowling ball in the Figure below is whizzing down the bowling lane at 4.0 m/s. If the mass of the bowling ball is 7.0 kg, what is its kinetic energy?

Answer 1

$\sf \Large Solution!!$

$\sf \large Given:$

$\sf \to v=4.0\:m/s$

$\sf \to m=7.0\:kg$

$\sf \large Formula:$

$\sf \to K=\dfrac{1}{2}mv^{2}$

$\sf \large So,$

$\sf \to K=\dfrac{1}{2}\times 7.0\:kg\times (4.0\:m/s)^{2}$

$\sf \to K=\dfrac{1}{\cancel 2}\times 7.0\:kg\times \cancel{16}\;^{8}m^{2}/s^{2}$

$\sf \to K=7\:kg\times 8\:m^{2}/s^{2}$

$\sf \bigstar K=56J$

Thanks for asking!! :)