Math, asked by ShreeSai3348, 8 months ago

The box plots show Devonte’s scores in Spanish and in French.


Spanish

2 box plots. The number line goes from 50 to 100. For Spanish, the whiskers range from 55 to 95, and the box ranges from 60 to 85. A line divides the box at 70. For French, the whiskers range from 55 to 90, and the box ranges from 65 to 80. A line divides the box at 75.

French


Devonte inferred that his French scores have less variability than his Spanish scores. Which explains whether Devonte’s inference is correct?

Devonte is correct because the range is greater for French.

Devonte is correct because the interquartile range is less for French.

Devonte is not correct because his highest grade is in Spanish.

Devonte is not correct because the interquartile range is less for Spanish.

Answers

Answered by RoastingQueen
7

Step-by-step explanation:

 \boxed {\begin{minipage}{7 cm}\\ \dag\underline{\Large\sf Formulas\:of\:Statistics} \\ \\ \bigstar\underline{\sf Mean:-} \\ \\ \bullet\sf M=\dfrac {\Sigma x}{n} \\ \bullet\sf M=a+\dfrac {\Sigma fy}{\Sigma f} \\ \\ \bullet\sf M=A +\dfrac {\Sigma fy^i}{\Sigma f}\times c \\ \\ \bigstar\underline{\sf Median} \\ \\ \bullet\sf M_d=\dfrac {n+1}{2} \:\left[\because n\:is\:odd\:number\right] \\ \bullet\sf M_d=\dfrac {1}{2}\left (\dfrac {n}{2}+\dfrac {n}{2}+1\right)\:\left[\because n\:is\:even\:number\right] \\ \\ \bullet\sf M_d=l+\dfrac {m-c}{f}\times i \\ \\ \bigstar{\boxed{\sf M_0=3M_d-2M}}\end {minipage}}

Similar questions