The Boyle temperature of a vander Waals gas
having a = 360.0 kPa dm'mol-2 and b = 0.0364
dm mol-1 is about
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1
Answer:
The temperature at which oxygen gas behaves ideally for a longer range of pressure is Boyle's temperature.
T
B
=
bR
a
=
0.0318Lmol
−1
×0.08206Latm/mol/K
1.36atmL
2
mol
−2
=521K
Hence, the temperature at which oxygen gas behaves ideally for a longer range of pressure is 521 K.
Hence, the correct option is A
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