Question

The boys and girls in a school are in the ratio 2:3 . If total strength of the school is 550, find the number of boys and girls​

Answer 1

$\rm{\underline{\underline\color{darkblue}{Given:-}}}$

• Ratio = 2 : 3.

• School students = 550

$\rm{\underline{\underline\color{darkblue}{Find:-}}}$

• Find the number of boys and girls.

$\rm{\underline{\underline\color{darkblue}{Solution:-}}}$

$\rm\mapsto{Sum \: of \: the \: \: terms \: of \: the \: ratio = 2+3=5.}$

$\rm\mapsto{ \: Total \: strength = 550}$

$\rm\mapsto{Boys \: strength = \frac{5}{2} \times 550 } \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \rm = 2.5 \times 550 \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 1375$

$\rm\mapsto{Girls \: strength = \frac{3}{5} \times 550 } \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \rm = 0.6 \times 550 \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 330$

$\rule{356mm}{2mm}$

Learn more :

$\begin{gathered}\begin{gathered}\end{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\small\bf\dag \: {\underline{More \: Formulae}} \\ \small\boxed{ \begin{array}{cc} \bigstar \: \sf{Gain = S.P - C.P} \\ \\ \bigstar \:\sf{Loss = C.P - S.P} \\ \\ \bigstar \: \sf{Gain \: \% = \Bigg( \dfrac{Gain}{C.P} \times 100 \Bigg)\%} \\ \\ \bigstar \: \sf{loss \: \% = \Bigg( \dfrac{loss}{C.P} \times 100 \Bigg)\%} \\ \\ \bigstar \: \sf{S.P = \dfrac{100+Gain\%}{100} \times C.P} \\ \\ \bigstar \: \sf{ C.P =\dfrac{100}{100+Gain\%} \times S.P} \\ \\\bigstar \: \sf{ S.P = \dfrac{100 - loss\%}{100} \times C.P} \\ \\ \bigstar \: \sf{ C.P =\dfrac{100}{100 - loss\%} \times S.P}\end{array} }\end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}$

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@Shivam