Question

The boys are aged 10 years,12years and 16years. they want to divide rupees 4560 in the ratio of their ages.how much money would each get
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Answer 1

Answer:

Step-by-step explanation:10x +12x+16x=4560

38x = 4560

x=120

10 years =10x =1200

12 years =12x =1440

16 years =16x =1920

Answer 2

Answer:

• 1st boy get Rs. 1200
• 2nd boy get Rs. 1440
• 3rd boy get Rs. 1920

Step-by-step explanation:

Given:

• No. of boys = 3
• Age of 1st boy = 10 yrs
• Age of 2nd boy = 12 yrs
• Age of 3rd boy = 16 yrs

To Find:

• How much money would each get?

Now, ratio of their ages are = 10:12:16.

Sum of their ages = 10 + 12 + 16

Sum of their ages = 38

Now, we will find how much money would each get,

$\sf 1st\;boy\;get=\dfrac{10}{38}\times 4560\\ \\ \\ \implies \sf 0.26 \times 4560\\ \\ \implies \sf 1200\;(Approx)\\ \\ \\ \underline{\bf Hence,\;1st\;boy\;get\;Rs.\;1200.}$

$\sf 2nd\;boy\;get=\dfrac{12}{38}\times 4560\\ \\ \\ \implies \sf 0.31 \times 4560\\ \\ \implies \sf 1440\;(Approx)\\ \\ \\ \underline{\bf Hence,\;2nd\;boy\;get\;Rs.\;1440.}$

$\sf 3rd\;boy\;get=\dfrac{16}{38}\times 4560\\ \\ \\ \implies \sf 0.42 \times 4560\\ \\ \implies \sf 1920\;(Approx)\\ \\ \\ \underline{\bf Hence,\;3rd\;boy\;get\;Rs.\;1920.}$