Question

The boys are standing in a row having chit numbered consecutively from 1 to 49. There is a boy having chit numbered 'x' such that the sum of numbers on chit preceding the boy is equal to the sum of the numbers on the chit following it. Find 'x'.

Answer 1

Therefore, the number on chit would be 35.

Step-by-step explanation:

Since the sum of numbers on chit preceding x = the sum of numbers on chit following x.

$S_{x-1}=S_{49} - S_{x}$

Therefore, $S_{n}=\frac{n(n+1)}{2}$

$\frac{(x-1)(x-1+1)}{2}=\frac{49(49+1)}{2}-\frac{x(x+1)}{2}$

$\frac{x(x-1)}{2}=\frac{49\times 50}{2}-\frac{x(x+1)}{2}$

$\frac{1}{2}[x(x-1)]=\frac{1}{2}[2450-x(x+1)]$

x(x-1) = 2450 - x(x + 1)

x² - x = 2450 - x² - x

x² - x + x² + x = 2450

2x² = 2450

x² = 1225

x = √1225

x = 35

Therefore, the number on chit would be 35.

Learn more about A.P. series : https://brainly.in/question/8574499

Answer 2

Answer:

answer is 35..

I hope this answer is correct