The brakes & tires of a car can provide a maximum deceleration of around 6m/s2.If a car is traveling at 100km/h what is the minimum distance in which it could stop?
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Answer:
64.31 m
Explanation:
According to the given question,
a = acceleration
it's asking minimum distance. We know for minimum distance, deceleration must be maximum.
and -a = deceleration = 6m/s^2
u = initial velocity = 100 km/h = 100×1000/3600 = 27.78 m/s
v = final velocity = 0 m/s
s = displacement
Here displacement is equal to the distance as it's a linear motion without changing it's direction.
We know,
- v^2 = u^2 + 2as
Putting the values we get,
- 0 = 771.72 - 2×6×s
- 12s = 771.72
- s = 771.72/12
- s = 64.31 m
Thus, distance travelled by the car is 64.31 m when it's deceleration is 6 m/s^2 and initial velocity is 100 km/h.
tavilefty666:
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