Question

THE BRAKES APPLIED TO A CAP PRODUCE A NEGATIVE ACCELLARATION OF 12 MS^-2 . IF THE CAR STOPS AFTER 2 SECONDS , THE INITIAL VELOCITY OF THE CAR IS ? I WILL MARK THE CORRECT AND PROPER EXPLAINED ANSWER AS BRAINLIEST PLEASE ANSWER STEP BY STEP

Answer 1

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✤ Required Answer:

✒ GiveN:

• Brakes were applied
• Negative acceleration of 12 m/s²
• Car stops in 2 sec

✒ To FinD:

• Find the initial velocity of the car....?

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✤ How to solve?

For solving the above question, we need to know the three equations of, They are:

• v = u + at
• s = ut + 1/2 at²
• v² = u² + 2as

When we have some of the quantities, given in the question and we need to find the other among the above. We can use these equations.

✒ Symbols have their usual meanings.

So, by using these equations, let's solve the equation.

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✤ Solution:

We have,

• a = -12 m/s² [Negative acceleration]
• t = 2 s

[As, brakes are applied finally the vehicle will stop, hence final velocity is equals to 0]

• v = 0 m/s

✒ We need to find initial velocity

By using 1st equation of motion,

➙ v = u + at

➙ 0 = u + (-12)2

➙ 0 = u - 24

➙ u = 24 m/s

✒ Therefore, Initial velocity of the car = 24 m/s$.$

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Answer 2

Answer:

Given :

☞︎︎︎ Final velocity = 0 (car comes to stop)

☞︎︎︎ Retardation = 12 m/s^2 or acceleration= -12m/s^2

☞︎︎︎ Time taken to stop = 2sec

To Find :

❥︎ Initial velocity of the car

Solution :

❦︎ Using first equation of motion:

$\boxed{\red{v=u+at}}$

where,

v refers to Final velocity

u refers to Initial velocity

a refers to acceleration

t refers to time taken

❥︎ putting the values in above equation ,we get :

➪ 0 = u +(-12)*2

➪ 0=u-24

➪ u = 24m/s

$\bf{\orange{\underline{\underline{Hence,\;the\;initial\;velocity\;of\;the\;car\;is\;24m/s}}}}$