Question

The brakes applied to a car produce a negative acceleration of 6m/s^2 lf the car takes 2s to stop after applying the brakes, calculate the distance it travels during the time

Answer 1

Answer:

12 m

Explanation:

Acceleration produced on applying brakes

= -6 m/(s)^2

Time taken to stop = 2 s

Let initial velocity be u m/s

final velocity is 0 m/s

Using equation of motion

v = u + at

0 = u +(-6)×(2)

u = 12 m/s

Now, using

(v)^2 - (u)^2 = 2as

(0)^2 - (12)^2 = 2 (-6)(s)

-144 = -12(s)

s = 12 m

Answer 2

$\sf \pmb{Answer :}$

12 m

Explanation:

Acceleration produced on applying brakes

= -6 m/(s)^2

Time taken to stop = 2 s

Let initial velocity be u m/s

final velocity is 0 m/s

Using equation of motion

v = u + at

0 = u +(-6)×(2)

u = 12 m/s

Now, using

(v)^2 - (u)^2 = 2as

(0)^2 - (12)^2 = 2 (-6)(s)

-144 = -12(s)

s = 12 m