Question

The brakes applied to a car produce a negative acceleration of 10 m/s^2 . If the car takes 5 seconds to stop after applying the brakes,calculate the distance covered by the car before coming to rest.

Answer 1

acceleration = -10m/s^2
time = 5sec
car has to come to rest so its final velocity is 0
v = u +at
0 = u + (-10*5)
0 = u -50
u=50
distance = 1/2at^2 + ut
distance = 1/2(10)(25) + (50)(5)
 375m

Answer 2

acceleration = -10m/s^2

time = 5sec

car has to come to rest so its final velocity is 0

v = u +at

0 = u + (-10*5)

0 = u -50

u=50

distance = 1/2at^2 + ut

distance = 1/2(10)(25) + (50)(5)

375m