Question

The brakes applied to a car produce a negative acceleration of 6m/s² . If the car takes 2s to stop after applying the brakes , Calculate the distance travelled by the car during this time . please to type out the working . ​

Answer 1

Answer :-

Distance travelled by the car in given time is 12 metres .

Explanation :-

We have :-

→ Acceleration of the car = -6 m/s²

→ Time taken to stop = 2 seconds

→ Final velocity = 0 m/s

[As the car finally stops] .

________________________________

Firstly, let's calculate the initial velocity of the car by using the 1st equation of motion .

v = u + at

⇒ 0 = u + (-6)2

⇒ 0 - u = -12

⇒ -u = -12

⇒ u = 12 m/s

Now, we can calculate the distance travelled by the car either by using the 2nd or 3rd equation of motion.

s = ut + ½at²

⇒ s = 12 × 2 + ½ × (-6) × (2)²

⇒ s = 24 + (-3)4

⇒ s = 24 + (-12)

⇒ s = 12 m

Answer 2

Given :-

The brakes applied to a car produce a negative acceleration of 6m/s² . If the car takes 2s to stop after applying the brakes ,

To Find :-

Distance travelled

Solution :-

We know that

v = u + at

0 = u + (-6)(2)

0 - u = (-6)(2)

-u = -12

u = 12 m/s

Now

v² - u² = 2as

(0)² - (12)² = 2(-6)(s)

0 - 144 = -12s

-144 = -12s

-144/-12 = s

144/12 = s

12 = s

[tex][/tex]