The brakes applied to a car produce a negative acceleration of 10m/s^2. If the car takes 5s to stop after applying brakes, calculate the distance covered by the car before coming to rest.
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see, here we can apply the second equation of motion which is:
=s=ut-1/2at^2
putting the value of the information
= s=vt+1/2at^2
=s=1/2*10*25
=s=125
please mark the answer as brainiest
hope it helped you!
=s=ut-1/2at^2
putting the value of the information
= s=vt+1/2at^2
=s=1/2*10*25
=s=125
please mark the answer as brainiest
hope it helped you!
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