Question

the brakes applied to a car produce acceleration of 6 metre per second square in the opposite direction of the motion if the car takes 2sec to stop after the acceleration of breaks calculate the travels during this time

Answer 1

Heya!

Let's just jot down the points given to us in the question.......

• Breaks are applied to produce an acceleration of 6 ms² in the opposite direction. This means Acceleration(a) = -6 m/s², where the minus sign indicates opposite direction.
• The car takes Time(t) = 2 s to stop after the breaks were applied.
• Here, Final velocity(v) = 0 m/s.

So, we need to find the distance traveled by the object in these 2 seconds.

By third equation of motion,

$v^2 - u^2 = 2as \\ \implies 0^2 - u^2 = 2(-6)(s) \\ \implies 0 - u^2 = -12s \\ \implies -u^2 = -12s \\ \implies u^2 = 12s \\ \implies ???????$

But, in the question, Initial Velocity(u) is not given and hence the question is incomplete.

#beBrainly#markAsBrainiest#followMe#tejasgupta

Thanks!