Question

The brakes applied to a car produce an acceleration of 12m per sec sq in the opposite direction of motion.If the car takes 2 sec to stop after the application of brakes,calculate the distance traveled by the car during this time

Answer 1

Answer :

Acceleration of car = -12m/s²

[፨ Negative sign shows retardation.]

Time taken by car to stop = 2s

We have to find distance covered by car before it is brought to rest$.$

First we have to find initial velocity of car.

Applied brakes produce retardation in motion of car.

Distance covered by moving object before it is brought to rest is called stopping distance$.$

☃ Let's solve this Question :D

◈ First eq. of kinematics :

➝ v = u + at

➝ 0 = u + (-12)(2)

➝ u = 24 m/s

◈ Third eq. of kinematics :

➝ v² - u² = 2as

➝ 0² - 24² = 2(-12)s

➝ s = 24²/24

➝ s = 24 m

Answer 2

Answer:

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