The brakes applied to a car produce an acceleration of 16 m /S² in the opposite direction to the motion if the car takes 23s to stop after application of brakes calculate the distance it travel during this time
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v=u-at
0=u-6 into 23
0=u-138
u=138
so,S=UT+1/2ATsquare
s=138into23+1/2 6into23
s=3174+69
s=3243m
hope it help you
0=u-6 into 23
0=u-138
u=138
so,S=UT+1/2ATsquare
s=138into23+1/2 6into23
s=3174+69
s=3243m
hope it help you
rohitmeena1982:
I have wote wrong question it is not 16 m/s² it's 6m/s²....... So sad
so i can edit it
ok if u cab
thank you very much
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