Question

the brakes applied to a car produce an acceleration of 4 metre per second square in the opposite direction to the motion if the car takes 3 seconds to stop after the application of brakes calculate the distance it travels during this time​

Answer 1

Here

v=0m/s

a=-4m/s^2

t=3 s

USING 1ST EQUATION OF MOTION

v=u+at

0=u-4×3

u=12m/s

s=ut +1/2at^2

=12×3+1/2×-4×9

36-18

=28m