Question

The brakes applied to a car produce an acceleration of 4 m/s2

in the opposite direction to the motion. If the car

takes 3s to stop after the application of brakes, calculate the distance it travels during this time.​

Answer 1

Answer:

ANSWER

Given:

Accerleration: a=−6 m/s

2

Time t=2 s

Final velocity, v=0 m/s

v=u+at

0=u−6×2

u=12 m/s

s=ut+

2

1

at

2

s=12×2+

2

1

×(−6)×4

⇒s=12 m

Explanation:

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