Question

the brakes applied to a car produce an acceleration of 5m/s^2 in opposite direction to the motion. if the car take 5 second to stop after the application of break, calculate the distance its travel during this time ?​

Answer 1

Answer:

Answer

Correct option is

A

12 m

Given:

Accerleration: a=−6 m/s

2

Time t=2 s

Final velocity, v=0 m/s

v=u+at

0=u−6×2

u=12 m/s

s=ut+

2

1

at

2

s=12×2+

2

1

×(−6)×4

⇒s=12 m