The brakes applied to a car produce an acceleration of 6 metre per second squared opposite motion car takes 25 to stop calculate distance
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a=-6 m/s sq
t=25 sec
v=0
u=?
u=v-at
=0-(-6) ×25
=150m/s
s=?
s=v sq -u sq /2 a
=0-150 ×150/2× -6
=22500/-12
= -1875m
t=25 sec
v=0
u=?
u=v-at
=0-(-6) ×25
=150m/s
s=?
s=v sq -u sq /2 a
=0-150 ×150/2× -6
=22500/-12
= -1875m
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