the brakes applied to a car produce an acceleration of 6 metre per second square in the opposite direction to the motion if the car takes two seconds to stop after the application of brakes calculate the distance travelled during this time
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v = u + at
0 = u + (-6)×2
u = 12 m/s
s = ut + 1/2 at*t
= 12×2 - 1/2×6×2×2
= 24 - 12
= 12m
0 = u + (-6)×2
u = 12 m/s
s = ut + 1/2 at*t
= 12×2 - 1/2×6×2×2
= 24 - 12
= 12m
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