Question

The brakes applied to a car
produce an acceleration of 6 m sin
the opposite direction to the motion. If
the car takes 2 s to stop after the
application of brakes, calculate the
distance it travels during this time.​

Answer 1

Answer:

a= -6m/sec^2

t=2 sec

v=0m/sec

distance=

a=v-u/t

-6=0-u/2

-u= -12

u=12 m/s

s=ut+1/2at^2

24+1/2×(-6)×4

24-24

0 m

Ans》0 m

Answer 2

Explanation:

given,

a= -6 m/s^

time taken=2s

v=0 m/s

using relation..

v=u+at

u= 12 m/s

using 2nd relation ...

s=ut +(1/2)×a×(t)^2

s=12×2+(1/2)×(-6)×(2)^2

s=24+(-12)

s=12 m

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hope my answer will be satisfied to you...