Question

The brakes applied to a car produce an acceleration of 6 m/s2 in the opposite direction of the motion. If the car takes 2 s to stop after the application of the breaks, calculate the distance it travels during this time.
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Answer 1

Answer:

36 metres

Explanation:

Given:

• Acceleration of the car = a = -6 m/s²
• Time taken for the car to stop = t = 2 seconds
• Final velocity of the car = v = 0 m/s

To find:

• Distance travelled by the car before it comes to rest

First using first equation of motion let us find initial velocity:

V=u+at

0=u-6×2

0=u-12

u=12 m/s

The initial velocity of the car is equal to 12 m/s

Now using second equation of motion:

S=ut+$\frac{1}{2}$at²

S=12×2+$\frac{1}{2} \times 6 \times 2^{2}$

S=24+12

S=36 metres

The car will cover a distance of 36 metres before coming to rest