The brakes applied to a car
produce an acceleration of 6 m sin
the opposite direction to the motion. If
the car takes 2 s to stop after the
application of brakes, calculate the
distance it travels during this time.
Answers
Answered by
0
Answer:
Explanation:
d to a car
produce an acceleration of 6 m sin
the opposite direction to the motion. If
the car takes 2 s to stop after the
application of brakes, calculate the
distance it travels during t
Answered by
1
Given:-
- Acceleration ,a = 6m/s² (acting in opposite direction)
- Final velocity ,v = 0m/s
- Time taken ,t = 2s
To Find:-
- Distance travelled ,s
Solution:-
According to the Question
Firstly we calculate the initial velocity of the car .
By using Kinematics Equation
- v = u + at
where,
- v is the final velocity
- a is the acceleration
- u is the initial velocity
- t is the time taken
Putting all the given value s we get
➺ 0 = u + (-6) × 2
➺ 0 = u -12
➺ -u = -12m/s
➺ u = 12m/s
So, the initial velocity of the car was 12m/s.
Now, calculating the distance covered by car . Again by using Kinematics Equation
- v² = u² + 2as
Substitute the value we get
➺ 0² = 12² + 2×(-6) × s
➺ 0 = 144 + (-12) × s
➺ -144 = -12× s
➺ 144 = 12×s
➺ s = 144/12
➺ s = 12m
- Hence, the distance covered by the car during this time is 12 metres.
Similar questions
English,
2 months ago
Computer Science,
2 months ago
English,
2 months ago
Science,
5 months ago
Political Science,
5 months ago
English,
10 months ago
Social Sciences,
10 months ago
Math,
10 months ago