The brakes applied to a car produce an acceleration of 6 m/s2 in the opposite direction to the motion. If the car takes 2s to stop after the application of brakes, calculate the distance it travels during this time.
Answers
Answered by
8
Solution:-
given by:-
》acceleration= 6m/s^2 , v= 0 , t= 2s u= find
by formula
》u = v+at
》u= 0+6×2
》u= 12m/s
by formula
》v^2 = u^2+2as
》0 = 144+2×(-6×s)
》-12s = -144
》s = 144/12
》s=12m
given by:-
》acceleration= 6m/s^2 , v= 0 , t= 2s u= find
by formula
》u = v+at
》u= 0+6×2
》u= 12m/s
by formula
》v^2 = u^2+2as
》0 = 144+2×(-6×s)
》-12s = -144
》s = 144/12
》s=12m
chirag2k17:
thanks for helping me.....
Similar questions