Question

The brakes applied to a car produce an acceleration of 6 m/s^2 in the opposite direction to the motion. If the car takes 3s to come to rest after the application of brakes, calculate (i) initial velocity of the car before applying brakes and (ii) the distance covered by the car before stopping.
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Answer 1

Answer:

first mark BRAINLIEST

Explanation:

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Answer 2

Acceleration

Distance

Final Velocity

v = u + a*t

Initial Velocity u

m/s

Final Velocity v

m/s

Time t

s

Acceleration a

m/s²

RESET VALUES

ANSWER

Given:

Accerleration: a=−6 m/s

2

Time t=2 s

Final velocity, v=0 m/s

v=u+at

0=u−6×2

u=12 m/s

s=ut+

2

1

at

2

s=12×2+

2

1

×(−6)×4

⇒s=12 m