Question

The brakes applied to a car
produce an acceleration of 6 m s-² in the opposite direction to the motion. If the car takes 2 s to stop after the application of brakes, calculate the
distance it travels during this time.



plz don't spam
I need the correct answer with explanation :)​

Answer 1

Explanation:

Given:

Accerleration: a=−6 m/s2

Time t=2 s

Final velocity, v=0 m/s

v=u+at

0=u−6×2

u=12 m/s

s=ut+ 21 at 2

s=12×2+ 21

×(−6)×4

⇒s=12 m

Answer 2

Given:

Acceleration of a car is 6 m/s².

Time, t = 2 sec.

To Find:

The distance travelled by car during this time.

Solution:

We know that,

The brakes applied to a car produces acceleration of 6 m/s².

Time taken to stop is 2 sec.

To find the distance = ?

First, we need to find the initial velocity, u = ?

Using,

V = u + at

Put the given values in the formula,

we get,

⟹ 0 = u - 6 × 2

⟹ 0 = u - 12

⟹ u = 12 m/s.

∴ Initial velocity of the car is 12 m/s.

Now,

To find the distance, S = ?

Using,

S = ut + 1/2 at²

Put the given values in the formula,

we get,

⟹ S = 12 × 2 + 1/2 × (-6) × 4

⟹ S = 12 × 1 × (-6) × 4

⟹ S = 24 - 12

⟹ S = 12 m/s.

∴ The distance travelled by the car during this time is 12 m/s.