The brakes applied to a car produce an acceleration of 6 m/(s)2 in the opposite direction of the motion. If the car takes 2 seconds to stop after application of brakes , calculate the distance it travels during this time
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This answer in the pic may help u
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A = 6m/s^2
T= 2 sec
V = 0m/s
U?
S?
V= u+at
U= v- at
U= 0-(6×2)
U= 12m/s
S= v^2 - u^2 / 2a
S= 0-144/-12
S= 12 m
Hope it helps!
T= 2 sec
V = 0m/s
U?
S?
V= u+at
U= v- at
U= 0-(6×2)
U= 12m/s
S= v^2 - u^2 / 2a
S= 0-144/-12
S= 12 m
Hope it helps!
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