The brakes applied to a car produce an acceleration of 6 m/s in the opposite direction .If the car stops in 2 sec calculate the distance travelled ?
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a=-6m/s^2
t=2sec
v=0m/s
u?
s?
v=u+at
u=v-at
u=0-(-6×2)
u=12m/s
s=v^2-u^2/2a
s= 0-144/-12
s=12m
t=2sec
v=0m/s
u?
s?
v=u+at
u=v-at
u=0-(-6×2)
u=12m/s
s=v^2-u^2/2a
s= 0-144/-12
s=12m
rishabh2004:
if it is helpful so please help me also
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