Question

. The brakes applied to a car produce an acceleration of 6 ms in the opp
to the motion. If the car takes 2 s to stop after the application of brakes, calculat
travels during this time.
es calculate the distance​

Answer 1

Answer:

v = 0 m/s. t=2 s. a= - 6m/s square

as, v=u+at

u= v- at

u = 0 -2(-6)

u = 12 m/s

as , s= ut + 1/2at square

s = 12(2). + 1/2* -6*2*2

s= 24. + (-12)

s = 24-12

s= 12 m

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