The brakes applied to a car produce an acceleration of 6 ms in the opposite direct to the motion. If the car takes 2 s to stop after the application of brakes, calculate the distance it travels during this time. ( with sum)
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Given a= -6m/s2 (acceleration in opposite direction)
V=0 m/s
t =2s
Initial velocity(u) = ?
Acc to first equation of motion V= u+at
0 = u + (-6m/s2) x 2s
u = 12m/s
Initial velocity of the bus is 12m/s.
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