Question

The brakes applied to a car produce an acceleration of 6m/s²in the opposite direction of the motion .if car takes 2sec to stop after the application of brakes ,calculate the distance it travels during this time

Answer 1

a = -6m/s2*
t = 2 sec
v = 0

Also, a = v- u/t
-6 = 0-u/2
-12= -u

s=ut+1/2at2
s=12×2 + 1/2×-6×2×2
s=24+(-12)
s=12m. Answer

Answer 2

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The brakes applied to a car produce an acceleration of 6m/s²in the opposite direction of the motion .if car takes 2sec to stop after the application of brakes ,calculate the distance it travels during this time?

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${ \huge{ \bold{ \underline{ \underline{ \orange{Answer:-}}}}}}$

✒Given : -

• Acceleration(a) = -6m/s²
• Time Taken(t) = 2s
• Final Velocity = 0m/s-¹

✒To Find : -

• Distance = ?

✒1st Equation : -

$\leadsto\sf{{ \small{ \bold{ \bold{ \bold{ \green{u=u+t}}}}}}}$

➦On Substituting Values : -

⇒v = u + at

⇒0 = u + ( -6m/s-² ) × 2s

☛u = 12m/s-¹

✒1st Equation : -

$\leadsto\sf{{ \small{ \bold{ \bold{ \bold{ \pink{s=ut+\dfrac{1}{2}\:{at}^{2}}}}}}}}$

➦On Substituting Values : -

⇒s = ut + 1/2 at ²

⇒12 × 2 + 1/2 × -6 × 2

⇒24m -12m

☛12m

➦Thus , the Distance travelled by the car is 12m