the brakes applied to a car produce an acceleration of 6m/2s in the opposite direction to the motion . if the car takes 2sec to stop after the application of brakes , calculate the distance it travels during this time
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Hi there !
Initial velocity = u
Final velocity = v = 0 [ as brakes are applied ]
acceleration = a = -6 m/s² [ retardation ]
Time = t = 2 sec
Equation of motion:-
v = u + at
0 = u + -6 × 2
u = 12 m/s
distance traveled = s
s = ut + 1/at²
= 12 × 2 + 1/2 × - 6 × 2× 2
= 24 + -12
= 12 meter
Initial velocity = u
Final velocity = v = 0 [ as brakes are applied ]
acceleration = a = -6 m/s² [ retardation ]
Time = t = 2 sec
Equation of motion:-
v = u + at
0 = u + -6 × 2
u = 12 m/s
distance traveled = s
s = ut + 1/at²
= 12 × 2 + 1/2 × - 6 × 2× 2
= 24 + -12
= 12 meter
shagufta21:
is this answer completed
ya
:)
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