The brakes applied to a car produce an acceleration of 6m/s square in the opposite direction to the motion. if the car takes 2 sec to come to the rest after application of brakes calculate distance travelled
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v= 0
a= -6m/s^2
t=2sec
u=?
s=?
v= u+at
u= 12m/s
s= ut+1/2at^2
s= 24 - 12
s= 12 m
a= -6m/s^2
t=2sec
u=?
s=?
v= u+at
u= 12m/s
s= ut+1/2at^2
s= 24 - 12
s= 12 m
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