The brakes applied to a car produce an acceleration of 6m/s^2
in opposite direction to
the motion. if the car takes 3 s to come to rest after application of brakes, calculate (i) the
initial velocity of car before applying brake (ii) distance covered by the car before
stopping.
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Explanation:
Given:
Accerleration: a=−6 m/s
2
Time t=2 s
Final velocity, v=0 m/s
v=u+at
0=u−6×2
u=12 m/s
s=ut+
2
1
at
2
s=12×2+
2
1
×(−6)×4
⇒s=12 m
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