The brakes applied to a car produce an acceleration of 6m/s squar in the oposite direction to the motion.if the car takes 2sec to stop after the application of brakes calculate the distance it travels during this time
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a=v-u/t
6=0-u/2
u=12
s=ut+1/2at²
s=12*2+1/2*6*2²
s=24+1/2*24
s=24+12
s=36m
6=0-u/2
u=12
s=ut+1/2at²
s=12*2+1/2*6*2²
s=24+1/2*24
s=24+12
s=36m
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