The brakes applied to a car produce an acceleration of 6ms-2 in the opposite direction to the motion . If the car takes 2s to stop after the application of brakes calculate the distance it travels during this time.[tex][/tex]c
Answers
Answered by
2
V=u+at
V=0 m/s and a=-6m/s^2
U=12m/s
V^2-u^2=2ax
X=-u^2/2a=-144/2*-6=12m
V=0 m/s and a=-6m/s^2
U=12m/s
V^2-u^2=2ax
X=-u^2/2a=-144/2*-6=12m
Similar questions