Question

The brakes applied to a car produced an acceleration of 6 ms-2 in the opposite direction of the motion. If the car takes 2s to stop after the application of brakes, calculate the distance it travels during this time.

Answer 1

By the application of Newton's second equation of motion:-

S=ut+1/2at²

S= 0+1/2 x 6 x 2 x 2

S= (6 x 2) m

S= 12 m

BE BRAINLY

Answer 2

Answer:12m

Explanation:a = -6 ms ^2 , t = 2 s , v = 0 ms^1 ,v = u + at

0 = (-6 ms^2)×2s

S = u t + 1/2 at ^2

24m - 12m

= 12m