the brakes applied to a car produces a deceleration of 10 meters per second squared.If the car takes 5 seconds after applying the brakes,calculate the distance covered by the car before coming to rest
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Given,
A= -10 m/s
U =?
V = 0
t = 5s
S=?
Using first equation of motion
V-U =at
0-U = -10*5
-U = -50
U = 50m/s
By using second equation of motion
V² - U² = 2as
0-50² = 2*10*S
2500 = 20s
S= 2500/20
S= 125m
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