Question

the brakes applied to a car produces an acceleration of 6mper secondin the opposite direction to the motion if the car takes 2 second to stop after the apply station of rakes calculate the distance it travels during this time ​

Answer 1

here, a=-6m/s and t=2sec and v=0. v= u+at

0= u-6x2

u= 12m/s

now,

s=ut+1/2at^2

=12x2-1/2x6x2

=48-6

s = 42m