Physics, asked by parishriang, 1 year ago

The brakes applied to a car produces an aceleration of 6m/s square in the opposite direction to the motoin. If the car takes two seconds to stop after the application of brakes then calculate the distance it travels during this time

Answers

Answered by chikki52
1

Answer:

Acceleration a = -6 m/s^2

Time t = 2 s

Final velocity v = 0 m/s

Let initial velocity be u

Let distance be s

v = u + at

So, 0 = u + (-6)(2)

So, u = 12 m/s

Now, s = ut + (1/2) at^2

So, s = 12(2) + (1/2)(-6)(2^2)

So, s = 24 - 12

So, s = 12 m

Thus, distance travelled is 12 m

Answered by sagarnirapure914
8

Answer:

Hey mate....

Here's ur answer :::::::::::::""""

Given : Acceleration (a) = 6m/s²

time (t) = 2s

final velocity (v) = 0m/s

We know that ,

v = u + at

0 = u + (6) × 2

.°. u = 12 m/s

Also,

s = ut + 1/2 at²

.. s = 12 * 2 + 0.5 * (6) * 2²

, s = 24 12

.°. s = 12 m.

Thus, the car will move 12 m before it stops after the application of brakes.

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