Question

the brakes applied to a train moving at 90 km per hour produces retardation of 5 m per second square what distance will it cover before coming to a stop

Answer 1

Initial velocity=90km/hr =90*5/18 =25m/s
Finally the velocity after applying brakes would be=0m/s
Acceleration is = -5m/second square
Applying 3rd equation of motion,
v*v-u*u =2as
0*0-25*25=2(-5)s
So, stopping distance would be,
S=-25*25/2(-5)
=62.5m
So ,it will travel a distance of 62.5m before coming to rest

Answer 2

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the brakes applied to a train moving at 90 km per hour produces retardation of 5 m per second square what distance will it cover before coming to a stop