Question

the brakes applied to a train moving at 90km/h produce a retardation of 5m/s square . what distance will it cover before coming to a stop?

Answer 1

A/q Initial speed = u = 90km/h = 90(5/18)

m/s = 25 m/s

Final speed = v = 0 Acceleration = a = -5 m/s sq.

Let the distance covered = s

Since, v2 = u2 + 2as

 0 = 25x25 +2x(-5)x s
 0 = 625 – 10s
 10s = 625 

s = 62.5 m

Answer 2

Explanation:

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