the brakes applied to a train produces an acceleration of 5m/s2 in opposite direction to the motion if the train takes 6 seconds to stop after the application of brakes calculate the distance it travelled during the time
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answer is s=12 m and please make me brainlist and f.o.l.l.o.w. me
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Answer:
Given:
Accerleration: a=−6 m/s
2
Time t=2 s
Final velocity, v=0 m/s
v=u+at
0=u−6×2
u=12 m/s
s=ut+
2
1
at
2
s=12×2+
2
1
×(−6)×4
⇒s=12 m
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