Question

the brakes applied to a train while moving at 90km/h produces a retardation of 5m/s^2 to stop . find the time taken to stop the train​

Answer 1

Answer:

Explanation:A/q Initial speed = u = 90km/h = 90(5/18)

m/s = 25 m/s

Final speed = v= 0 Acceleration = a = -5 m/s sq.

Let the distance covered = s

Since, v2 = u2 + 2as

0 = 25x25 +2x(-5)x s 0625-10s

10s = 625

s = 62.5 m

Answer 2

Answer:

u=90km=0.09m

v=o

a=-5m

v=u+at

0=0.09+(-5t)

-0.09/-5=t

=0.018 s=time