The brakes applied to car produce an acceleration of 6m/s2 in opposite direction to the motion . if the car takes 2 seconds to stop the application of brakes .calculated the distance it travel during this time
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heya mate here is ur answer
given:. acceleration = 6ms^-2
time= 2s
then by Newton's equation of motion we have
v= u+ at
since v= 0
it becomes
u= -at
u= -6×2
u=-12ms^-1
then distance travelled while brake applied to still it stops is given by
v^2-u^2=2as
since , v=0
(-u)^2= 2as
(12)^2= 2×6×s
144= 12s
s= 144÷12 = 12m
hope it helps u
##########be brainly###############
given:. acceleration = 6ms^-2
time= 2s
then by Newton's equation of motion we have
v= u+ at
since v= 0
it becomes
u= -at
u= -6×2
u=-12ms^-1
then distance travelled while brake applied to still it stops is given by
v^2-u^2=2as
since , v=0
(-u)^2= 2as
(12)^2= 2×6×s
144= 12s
s= 144÷12 = 12m
hope it helps u
##########be brainly###############
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